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时间:2010-06-01 00:28来源:蓝天飞行翻译 作者:admin
曝光台 注意防骗 网曝天猫店富美金盛家居专营店坑蒙拐骗欺诈消费者

                                    - 0.03894
The drag is given by
                D - l2p'V2SCD
                                           =  ~ (1.225 * 0.864)44.442 * 27.75 * 0.03294
                            ~ 1129.3456 N
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62                  PERFORMANCE, STABIUTY, DYNAMICS, AND CONTROL
                                                    Example 1.2
     A two-dimensional wing was tested in a wind tunnel, and the pitching-moment
coefficient about the leading edge at zero-lift was found to be equal to -0.02. At
u = 8 deg, CL  - 0.7, Cd - 0.04, and Cm.,t - -0.20, determine the location of the
aerodynamic center.
Solution.   From Eq. (1.37),
Cm = Cmac - Xoc CL
We have Crnac - Cmo -. - 0.02, and Ci - 0.7, Cm = -0,2 at a - 8 deg. Then,
                                            Cmo - Cm
                           xac - -
                  Cl
                                               -0.02 - (-0.20)
                                                                                             =                     0-. 7
                                    - 0.2571
Thus, the aerodynamic center is located at 25.71eVo chord from Lhe leading-edge.
Example 1.3
      Deternune the mean aerodynamic chord and its spanwise location for an aircraft
wing having a root chord of 6.1 m, tip chord of 3.28 m, leading-edge sweep of
30 deg, and a semispan of 15.25 m.
So/ution.   From Eqs. (1.25) and (1.26), we have
- = 24,r(::-+A) )
                        )
    ymac =  :(L++2A} )
We have Cr - 6.1, b - 2 * 15.25 - 30.5, and the taper ratio A = 3.28/6.1  -
0.5377. Substituting, we get
  c - 4.8313 m
yIWK = 6.8608 m
  Example 1.4
  For a straight rectangular wing having a chord of 3 m and a span of 15 m,
determine the skin-friction coefficient and slan-friction drag at a velocity of 50
m/s, assuming the boundary layer to be laminar and the boundary layer to'9e fully
turbulent. Assume p - 1.225 kg/m3 and v = 1.4607 x 10-5 rri2/s.
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