动力机械和机身手册2(149)

曝光台 注意防骗 网曝天猫店富美金盛家居专营店坑蒙拐骗欺诈消费者

Substituting, we get the strip theory value of (Clp)W = -0.9595/rad.
      Now let us determine the valr                                    ie Datcom   method. We have
                   (qp,W = (  - -)::_:p(,jS(,,,,:,:,)/rad
We a\ssumek = l.Oand p = Jj;lj~ = 0.9797.FromFig.  4.25,(pcip/k)cL =O
= -0.43 for ALE - 0, A,--l.0, and A -. 6.0. Because F = O, we find [(qP)r]
(Clp)r=01 = 1.0. With these values, we get (Clp)W = -0.430/rad. Therefore,
the strip theory result differs from the Datcom value considerably, by as much as
lOOgro.
Now let us estimate (Cnp)W. The strip theory gives
                             (Cnp)W = -g(CL - CDa)/rad
Substituting the required values, we get (Cnp)W - -0.0831-Urad.
   Datcoml gives
  (Cnp)W=Clptana,(K-l)+K(CC c~= CLlrad
                                                                                                                                    L = O,M
                                       A +4 cos r                     +0.5(AB + cos Ac/4)ta
     = AB+4 AAt,.,.t,)[A2:[ _ ~At,,]
 ( CC,  ),, = O,M                                                                                       + 0.5(A  +  cos Ac/4)tanl
     x (C~ c =o/rad
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PERFORMANCE, STABILITY, DYNAMICS, AND CONTROL
(CC,)c,=o=_[A+6  cA+osAct4)(:-, +   ]
                                                                  A +4 cos Ac/4
               (CLct)e       (CLcr)e
K=~:} a"==n_Ae aw2=~A
    1.1CIA
           e= R u     .+ 1R)7rA
R = ai}~ + a217j + a3AI + a4
ai - 0.0004      a2 ~ -0.0080     a3 - 0.0501      a4 - 0.8642
We have
i.    AA
Ai -
  'I      cos ALE
     ao
CLr,e = ~+ _
Substituting ao - 0.1 *57.3 - 5.73/rad and A - 6, we get CUr,e = 0.0767/deg
or 4.3943/rad. With this, CL -. CIAr.ea - 0.3834. Further using Ac/4 = 0 and
A = 1.0, we get R - 0.9632, e - 0.9812, and K  - 0.9942.
   We have B =                     ~- = 1- Substituting, we get (CnplCL)C =O =
(Crip/CL)CL~.M = -0.6 and- (Cnp)W~ -0.2285. Therefore, the stnip theory
　
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